(3x+6)=(8x-16)+(2x+2)

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Solution for (3x+6)=(8x-16)+(2x+2) equation: 



(3x+6)=(8x-16)+(2x+2)

We move all terms to the left:

(3x+6)-((8x-16)+(2x+2))=0

We get rid of parentheses

3x-((8x-16)+(2x+2))+6=0



We calculate terms in parentheses: -((8x-16)+(2x+2)), so:

(8x-16)+(2x+2)

We get rid of parentheses

8x+2x-16+2

We add all the numbers together, and all the variables

10x-14

Back to the equation:

-(10x-14)



We get rid of parentheses

3x-10x+14+6=0

We add all the numbers together, and all the variables

-7x+20=0

We move all terms containing x to the left, all other terms to the right

-7x=-20

x=-20/-7

x=2+6/7

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