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(3x+6)=(x-10)=(x-11)
We move all terms to the left:
(3x+6)-((x-10))=0
We get rid of parentheses
3x-((x-10))+6=0
We calculate terms in parentheses: -((x-10)), so:We get rid of parentheses
(x-10)
We get rid of parentheses
x-10
Back to the equation:
-(x-10)
3x-x+10+6=0
We add all the numbers together, and all the variables
2x+16=0
We move all terms containing x to the left, all other terms to the right
2x=-16
x=-16/2
x=-8
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