(3x+6)=2(x+3)+10

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Solution for (3x+6)=2(x+3)+10 equation:



(3x+6)=2(x+3)+10
We move all terms to the left:
(3x+6)-(2(x+3)+10)=0
We get rid of parentheses
3x-(2(x+3)+10)+6=0
We calculate terms in parentheses: -(2(x+3)+10), so:
2(x+3)+10
We multiply parentheses
2x+6+10
We add all the numbers together, and all the variables
2x+16
Back to the equation:
-(2x+16)
We get rid of parentheses
3x-2x-16+6=0
We add all the numbers together, and all the variables
x-10=0
We move all terms containing x to the left, all other terms to the right
x=10

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