(3x+6)=2(x+3)+10

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Solution for (3x+6)=2(x+3)+10 equation: 



(3x+6)=2(x+3)+10

We move all terms to the left:

(3x+6)-(2(x+3)+10)=0

We get rid of parentheses

3x-(2(x+3)+10)+6=0



We calculate terms in parentheses: -(2(x+3)+10), so:

2(x+3)+10

We multiply parentheses

2x+6+10

We add all the numbers together, and all the variables

2x+16

Back to the equation:

-(2x+16)



We get rid of parentheses

3x-2x-16+6=0

We add all the numbers together, and all the variables

x-10=0

We move all terms containing x to the left, all other terms to the right

x=10

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