(3x+6/3)-(4x/x-2)=x

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Solution for (3x+6/3)-(4x/x-2)=x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3*x-((4*x)/x)+6/3+2 = x // - x

3*x-x-((4*x)/x)+6/3+2 = 0

3*x-x+6/3-4+2 = 0

2*x = 0 // : 2

x = 0

x in { 0} 

x belongs to the empty set

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