(3x+60)/5=40-x

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Solution for (3x+60)/5=40-x equation:



(3x+60)/5=40-x
We move all terms to the left:
(3x+60)/5-(40-x)=0
We add all the numbers together, and all the variables
(3x+60)/5-(-1x+40)=0
We get rid of parentheses
(3x+60)/5+1x-40=0
We multiply all the terms by the denominator
(3x+60)+1x*5-40*5=0
We add all the numbers together, and all the variables
(3x+60)+1x*5-200=0
Wy multiply elements
(3x+60)+5x-200=0
We get rid of parentheses
3x+5x+60-200=0
We add all the numbers together, and all the variables
8x-140=0
We move all terms containing x to the left, all other terms to the right
8x=140
x=140/8
x=17+1/2

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