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(3x+63)=(2x+92)
We move all terms to the left:
(3x+63)-((2x+92))=0
We get rid of parentheses
3x-((2x+92))+63=0
We calculate terms in parentheses: -((2x+92)), so:We get rid of parentheses
(2x+92)
We get rid of parentheses
2x+92
Back to the equation:
-(2x+92)
3x-2x-92+63=0
We add all the numbers together, and all the variables
x-29=0
We move all terms containing x to the left, all other terms to the right
x=29
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