(3x+63)=(6x+12)

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Solution for (3x+63)=(6x+12) equation: 



(3x+63)=(6x+12)

We move all terms to the left:

(3x+63)-((6x+12))=0

We get rid of parentheses

3x-((6x+12))+63=0



We calculate terms in parentheses: -((6x+12)), so:

(6x+12)

We get rid of parentheses

6x+12

Back to the equation:

-(6x+12)



We get rid of parentheses

3x-6x-12+63=0

We add all the numbers together, and all the variables

-3x+51=0

We move all terms containing x to the left, all other terms to the right

-3x=-51

x=-51/-3

x=+17

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