(3x+67)=(4x+50)

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Solution for (3x+67)=(4x+50) equation: 



(3x+67)=(4x+50)

We move all terms to the left:

(3x+67)-((4x+50))=0

We get rid of parentheses

3x-((4x+50))+67=0



We calculate terms in parentheses: -((4x+50)), so:

(4x+50)

We get rid of parentheses

4x+50

Back to the equation:

-(4x+50)



We get rid of parentheses

3x-4x-50+67=0

We add all the numbers together, and all the variables

-1x+17=0

We move all terms containing x to the left, all other terms to the right

-x=-17

x=-17/-1

x=+17

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