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(3x+6x)=2(4x-3)
We move all terms to the left:
(3x+6x)-(2(4x-3))=0
We add all the numbers together, and all the variables
(+9x)-(2(4x-3))=0
We get rid of parentheses
9x-(2(4x-3))=0
We calculate terms in parentheses: -(2(4x-3)), so:We get rid of parentheses
2(4x-3)
We multiply parentheses
8x-6
Back to the equation:
-(8x-6)
9x-8x+6=0
We add all the numbers together, and all the variables
x+6=0
We move all terms containing x to the left, all other terms to the right
x=-6
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