(3x+6x)=2(4x-3)

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Solution for (3x+6x)=2(4x-3) equation: 



(3x+6x)=2(4x-3)

We move all terms to the left:

(3x+6x)-(2(4x-3))=0

We add all the numbers together, and all the variables

(+9x)-(2(4x-3))=0

We get rid of parentheses

9x-(2(4x-3))=0



We calculate terms in parentheses: -(2(4x-3)), so:

2(4x-3)

We multiply parentheses

8x-6

Back to the equation:

-(8x-6)



We get rid of parentheses

9x-8x+6=0

We add all the numbers together, and all the variables

x+6=0

We move all terms containing x to the left, all other terms to the right

x=-6

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