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(3x+7)(-4x-6)=0
We multiply parentheses ..
(-12x^2-18x-28x-42)=0
We get rid of parentheses
-12x^2-18x-28x-42=0
We add all the numbers together, and all the variables
-12x^2-46x-42=0
a = -12; b = -46; c = -42;
Δ = b2-4ac
Δ = -462-4·(-12)·(-42)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-10}{2*-12}=\frac{36}{-24} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+10}{2*-12}=\frac{56}{-24} =-2+1/3 $
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