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(3x+7)(7x+4)=0
We multiply parentheses ..
(+21x^2+12x+49x+28)=0
We get rid of parentheses
21x^2+12x+49x+28=0
We add all the numbers together, and all the variables
21x^2+61x+28=0
a = 21; b = 61; c = +28;
Δ = b2-4ac
Δ = 612-4·21·28
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(61)-37}{2*21}=\frac{-98}{42} =-2+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(61)+37}{2*21}=\frac{-24}{42} =-4/7 $
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