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(3x+7)(x+3)=-16
We move all terms to the left:
(3x+7)(x+3)-(-16)=0
We add all the numbers together, and all the variables
(3x+7)(x+3)+16=0
We multiply parentheses ..
(+3x^2+9x+7x+21)+16=0
We get rid of parentheses
3x^2+9x+7x+21+16=0
We add all the numbers together, and all the variables
3x^2+16x+37=0
a = 3; b = 16; c = +37;
Δ = b2-4ac
Δ = 162-4·3·37
Δ = -188
Delta is less than zero, so there is no solution for the equation
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