(3x+7)+(3x+6)+(3x)=(3x)+(3x)+(4x+7)

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Solution for (3x+7)+(3x+6)+(3x)=(3x)+(3x)+(4x+7) equation: 



(3x+7)+(3x+6)+(3x)=(3x)+(3x)+(4x+7)

We move all terms to the left:

(3x+7)+(3x+6)+(3x)-((3x)+(3x)+(4x+7))=0

We add all the numbers together, and all the variables

3x+(3x+7)+(3x+6)-(3x+3x+(4x+7))=0

We get rid of parentheses

3x+3x+3x-(3x+3x+(4x+7))+7+6=0



We calculate terms in parentheses: -(3x+3x+(4x+7)), so:

3x+3x+(4x+7)

We add all the numbers together, and all the variables

6x+(4x+7)

We get rid of parentheses

6x+4x+7

We add all the numbers together, and all the variables

10x+7

Back to the equation:

-(10x+7)



We add all the numbers together, and all the variables

9x-(10x+7)+13=0

We get rid of parentheses

9x-10x-7+13=0

We add all the numbers together, and all the variables

-1x+6=0

We move all terms containing x to the left, all other terms to the right

-x=-6

x=-6/-1

x=+6

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