(3x+7)+(3x+6)+(3x)=(3x)+(3x)+(4x+8)

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Solution for (3x+7)+(3x+6)+(3x)=(3x)+(3x)+(4x+8) equation: 



(3x+7)+(3x+6)+(3x)=(3x)+(3x)+(4x+8)

We move all terms to the left:

(3x+7)+(3x+6)+(3x)-((3x)+(3x)+(4x+8))=0

We add all the numbers together, and all the variables

3x+(3x+7)+(3x+6)-(3x+3x+(4x+8))=0

We get rid of parentheses

3x+3x+3x-(3x+3x+(4x+8))+7+6=0



We calculate terms in parentheses: -(3x+3x+(4x+8)), so:

3x+3x+(4x+8)

We add all the numbers together, and all the variables

6x+(4x+8)

We get rid of parentheses

6x+4x+8

We add all the numbers together, and all the variables

10x+8

Back to the equation:

-(10x+8)



We add all the numbers together, and all the variables

9x-(10x+8)+13=0

We get rid of parentheses

9x-10x-8+13=0

We add all the numbers together, and all the variables

-1x+5=0

We move all terms containing x to the left, all other terms to the right

-x=-5

x=-5/-1

x=+5

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