(3x+7)/9=(-9x-5)/5

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Solution for (3x+7)/9=(-9x-5)/5 equation: 



(3x+7)/9=(-9x-5)/5

We move all terms to the left:

(3x+7)/9-((-9x-5)/5)=0

We calculate fractions


3x/()+(-((-9x-5)*9)/()=0



We calculate terms in parentheses: +(-((-9x-5)*9)/(), so:

-((-9x-5)*9)/(

We multiply all the terms by the denominator


-((-9x-5)*9)



We calculate terms in parentheses: -((-9x-5)*9), so:

(-9x-5)*9

We multiply parentheses

-81x-45

Back to the equation:

-(-81x-45)



We get rid of parentheses

81x+45

Back to the equation:

+(81x+45)



We get rid of parentheses

3x/()+81x+45=0

We multiply all the terms by the denominator


3x+81x*()+45*()=0

We add all the numbers together, and all the variables

3x+81x*()=0

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