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(3x+7/6x)+(1/x)=1
We move all terms to the left:
(3x+7/6x)+(1/x)-(1)=0
Domain of the equation: 6x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+3x+7/6x)+(+1/x)-1=0
We get rid of parentheses
3x+7/6x+1/x-1=0
We calculate fractions
3x+7x/6x^2+6x/6x^2-1=0
We multiply all the terms by the denominator
3x*6x^2+7x+6x-1*6x^2=0
We add all the numbers together, and all the variables
13x+3x*6x^2-1*6x^2=0
Wy multiply elements
18x^3-6x^2+13x=0
We do not support expression: x^3
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