(3x+70)=(7x+30)

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Solution for (3x+70)=(7x+30) equation: 



(3x+70)=(7x+30)

We move all terms to the left:

(3x+70)-((7x+30))=0

We get rid of parentheses

3x-((7x+30))+70=0



We calculate terms in parentheses: -((7x+30)), so:

(7x+30)

We get rid of parentheses

7x+30

Back to the equation:

-(7x+30)



We get rid of parentheses

3x-7x-30+70=0

We add all the numbers together, and all the variables

-4x+40=0

We move all terms containing x to the left, all other terms to the right

-4x=-40

x=-40/-4

x=+10

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