(3x+8)+(2x+21)=(6x+10)

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Solution for (3x+8)+(2x+21)=(6x+10) equation: 



(3x+8)+(2x+21)=(6x+10)

We move all terms to the left:

(3x+8)+(2x+21)-((6x+10))=0

We get rid of parentheses

3x+2x-((6x+10))+8+21=0



We calculate terms in parentheses: -((6x+10)), so:

(6x+10)

We get rid of parentheses

6x+10

Back to the equation:

-(6x+10)



We add all the numbers together, and all the variables

5x-(6x+10)+29=0

We get rid of parentheses

5x-6x-10+29=0

We add all the numbers together, and all the variables

-1x+19=0

We move all terms containing x to the left, all other terms to the right

-x=-19

x=-19/-1

x=+19

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