(3x+8)+(2x+4)=32

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Solution for (3x+8)+(2x+4)=32 equation: 



(3x+8)+(2x+4)=32

We move all terms to the left:

(3x+8)+(2x+4)-(32)=0

We get rid of parentheses

3x+2x+8+4-32=0

We add all the numbers together, and all the variables

5x-20=0

We move all terms containing x to the left, all other terms to the right

5x=20

x=20/5

x=4

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