(3x+8)+(3x+8)=(2x+20)

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Solution for (3x+8)+(3x+8)=(2x+20) equation: 



(3x+8)+(3x+8)=(2x+20)

We move all terms to the left:

(3x+8)+(3x+8)-((2x+20))=0

We get rid of parentheses

3x+3x-((2x+20))+8+8=0



We calculate terms in parentheses: -((2x+20)), so:

(2x+20)

We get rid of parentheses

2x+20

Back to the equation:

-(2x+20)



We add all the numbers together, and all the variables

6x-(2x+20)+16=0

We get rid of parentheses

6x-2x-20+16=0

We add all the numbers together, and all the variables

4x-4=0

We move all terms containing x to the left, all other terms to the right

4x=4

x=4/4

x=1

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