(3x+8)+(60-x)+(4x-38)=180

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Solution for (3x+8)+(60-x)+(4x-38)=180 equation: 



(3x+8)+(60-x)+(4x-38)=180

We move all terms to the left:

(3x+8)+(60-x)+(4x-38)-(180)=0

We add all the numbers together, and all the variables

(3x+8)+(-1x+60)+(4x-38)-180=0

We get rid of parentheses

3x-1x+4x+8+60-38-180=0

We add all the numbers together, and all the variables

6x-150=0

We move all terms containing x to the left, all other terms to the right

6x=150

x=150/6

x=25

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