(3x+8)+(6x-28)=90

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Solution for (3x+8)+(6x-28)=90 equation: 



(3x+8)+(6x-28)=90

We move all terms to the left:

(3x+8)+(6x-28)-(90)=0

We get rid of parentheses

3x+6x+8-28-90=0

We add all the numbers together, and all the variables

9x-110=0

We move all terms containing x to the left, all other terms to the right

9x=110

x=110/9

x=12+2/9

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