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(3x+8)/(9x+4)=3/8
We move all terms to the left:
(3x+8)/(9x+4)-(3/8)=0
Domain of the equation: (9x+4)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
9x!=-4
x!=-4/9
x!=-4/9
x∈R
(3x+8)/(9x+4)-(+3/8)=0
We get rid of parentheses
(3x+8)/(9x+4)-3/8=0
We calculate fractions
(24x+64)/(72x+32)+(-27x-12)/(72x+32)=0
We multiply all the terms by the denominator
(24x+64)+(-27x-12)=0
We get rid of parentheses
24x-27x+64-12=0
We add all the numbers together, and all the variables
-3x+52=0
We move all terms containing x to the left, all other terms to the right
-3x=-52
x=-52/-3
x=17+1/3
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