(3x+8)/5=(1-2x)/2

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Solution for (3x+8)/5=(1-2x)/2 equation: 



(3x+8)/5=(1-2x)/2

We move all terms to the left:

(3x+8)/5-((1-2x)/2)=0

We add all the numbers together, and all the variables

(3x+8)/5-((-2x+1)/2)=0

We calculate fractions


3x/()+(-((-2x+1)*5)/()=0



We calculate terms in parentheses: +(-((-2x+1)*5)/(), so:

-((-2x+1)*5)/(

We multiply all the terms by the denominator


-((-2x+1)*5)



We calculate terms in parentheses: -((-2x+1)*5), so:

(-2x+1)*5

We multiply parentheses

-10x+5

Back to the equation:

-(-10x+5)



We get rid of parentheses

10x-5

Back to the equation:

+(10x-5)



We get rid of parentheses

3x/()+10x-5=0

We multiply all the terms by the denominator


3x+10x*()-5*()=0

We add all the numbers together, and all the variables

3x+10x*()=0

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