(3x+8)=(2x+9)+(8x-16)

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Solution for (3x+8)=(2x+9)+(8x-16) equation: 



(3x+8)=(2x+9)+(8x-16)

We move all terms to the left:

(3x+8)-((2x+9)+(8x-16))=0

We get rid of parentheses

3x-((2x+9)+(8x-16))+8=0



We calculate terms in parentheses: -((2x+9)+(8x-16)), so:

(2x+9)+(8x-16)

We get rid of parentheses

2x+8x+9-16

We add all the numbers together, and all the variables

10x-7

Back to the equation:

-(10x-7)



We get rid of parentheses

3x-10x+7+8=0

We add all the numbers together, and all the variables

-7x+15=0

We move all terms containing x to the left, all other terms to the right

-7x=-15

x=-15/-7

x=2+1/7

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