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(3x+8)=(2x-2)
We move all terms to the left:
(3x+8)-((2x-2))=0
We get rid of parentheses
3x-((2x-2))+8=0
We calculate terms in parentheses: -((2x-2)), so:We get rid of parentheses
(2x-2)
We get rid of parentheses
2x-2
Back to the equation:
-(2x-2)
3x-2x+2+8=0
We add all the numbers together, and all the variables
x+10=0
We move all terms containing x to the left, all other terms to the right
x=-10
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