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(3x+8)x=210
We move all terms to the left:
(3x+8)x-(210)=0
We multiply parentheses
3x^2+8x-210=0
a = 3; b = 8; c = -210;
Δ = b2-4ac
Δ = 82-4·3·(-210)
Δ = 2584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2584}=\sqrt{4*646}=\sqrt{4}*\sqrt{646}=2\sqrt{646}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{646}}{2*3}=\frac{-8-2\sqrt{646}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{646}}{2*3}=\frac{-8+2\sqrt{646}}{6} $
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