(3x+8)x=270

Solution for (3x+8)x=270 equation:

(3x+8)x=270

We move all terms to the left:

(3x+8)x-(270)=0

We multiply parentheses

3x^2+8x-270=0

a = 3; b = 8; c = -270;
Δ = b2-4ac
Δ = 82-4·3·(-270)
Δ = 3304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3304}=\sqrt{4*826}=\sqrt{4}*\sqrt{826}=2\sqrt{826}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{826}}{2*3}=\frac{-8-2\sqrt{826}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{826}}{2*3}=\frac{-8+2\sqrt{826}}{6}
$