(3x+8/4)+(x+44/6)=13

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Solution for (3x+8/4)+(x+44/6)=13 equation:



(3x+8/4)+(x+44/6)=13
We move all terms to the left:
(3x+8/4)+(x+44/6)-(13)=0
We add all the numbers together, and all the variables
(3x+2)+(+x+44/6)-13=0
We get rid of parentheses
3x+x+2-13+44/6=0
We multiply all the terms by the denominator
3x*6+x*6+44+2*6-13*6=0
We add all the numbers together, and all the variables
3x*6+x*6-22=0
Wy multiply elements
18x+6x-22=0
We add all the numbers together, and all the variables
24x-22=0
We move all terms containing x to the left, all other terms to the right
24x=22
x=22/24
x=11/12

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