(3x+88)+(2x-4)+(x+36)=180

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Solution for (3x+88)+(2x-4)+(x+36)=180 equation:



(3x+88)+(2x-4)+(x+36)=180
We move all terms to the left:
(3x+88)+(2x-4)+(x+36)-(180)=0
We get rid of parentheses
3x+2x+x+88-4+36-180=0
We add all the numbers together, and all the variables
6x-60=0
We move all terms containing x to the left, all other terms to the right
6x=60
x=60/6
x=10

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