(3x+9)(4x+12)=0

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Solution for (3x+9)(4x+12)=0 equation:



(3x+9)(4x+12)=0
We multiply parentheses ..
(+12x^2+36x+36x+108)=0
We get rid of parentheses
12x^2+36x+36x+108=0
We add all the numbers together, and all the variables
12x^2+72x+108=0
a = 12; b = 72; c = +108;
Δ = b2-4ac
Δ = 722-4·12·108
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-72}{24}=-3$

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