(3x+9)+(2x+24)=(6x+15)

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Solution for (3x+9)+(2x+24)=(6x+15) equation: 



(3x+9)+(2x+24)=(6x+15)

We move all terms to the left:

(3x+9)+(2x+24)-((6x+15))=0

We get rid of parentheses

3x+2x-((6x+15))+9+24=0



We calculate terms in parentheses: -((6x+15)), so:

(6x+15)

We get rid of parentheses

6x+15

Back to the equation:

-(6x+15)



We add all the numbers together, and all the variables

5x-(6x+15)+33=0

We get rid of parentheses

5x-6x-15+33=0

We add all the numbers together, and all the variables

-1x+18=0

We move all terms containing x to the left, all other terms to the right

-x=-18

x=-18/-1

x=+18

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