(3x+9)+(3x+8)+(3x)=(4x-6)+2(3x)

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Solution for (3x+9)+(3x+8)+(3x)=(4x-6)+2(3x) equation: 



(3x+9)+(3x+8)+(3x)=(4x-6)+2(3x)

We move all terms to the left:

(3x+9)+(3x+8)+(3x)-((4x-6)+2(3x))=0

We add all the numbers together, and all the variables

3x+(3x+9)+(3x+8)-((4x-6)+23x)=0

We get rid of parentheses

3x+3x+3x-((4x-6)+23x)+9+8=0



We calculate terms in parentheses: -((4x-6)+23x), so:

(4x-6)+23x

We add all the numbers together, and all the variables

23x+(4x-6)

We get rid of parentheses

23x+4x-6

We add all the numbers together, and all the variables

27x-6

Back to the equation:

-(27x-6)



We add all the numbers together, and all the variables

9x-(27x-6)+17=0

We get rid of parentheses

9x-27x+6+17=0

We add all the numbers together, and all the variables

-18x+23=0

We move all terms containing x to the left, all other terms to the right

-18x=-23

x=-23/-18

x=1+5/18

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