(3x+9)=(11x-71)

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Solution for (3x+9)=(11x-71) equation: 



(3x+9)=(11x-71)

We move all terms to the left:

(3x+9)-((11x-71))=0

We get rid of parentheses

3x-((11x-71))+9=0



We calculate terms in parentheses: -((11x-71)), so:

(11x-71)

We get rid of parentheses

11x-71

Back to the equation:

-(11x-71)



We get rid of parentheses

3x-11x+71+9=0

We add all the numbers together, and all the variables

-8x+80=0

We move all terms containing x to the left, all other terms to the right

-8x=-80

x=-80/-8

x=+10

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