(3x-+20)=(10x-22)

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Solution for (3x-+20)=(10x-22) equation: 



(3x-+20)=(10x-22)

We move all terms to the left:

(3x-+20)-((10x-22))=0

We add all the numbers together, and all the variables

(+3x)-((10x-22))=0

We get rid of parentheses

3x-((10x-22))=0



We calculate terms in parentheses: -((10x-22)), so:

(10x-22)

We get rid of parentheses

10x-22

Back to the equation:

-(10x-22)



We get rid of parentheses

3x-10x+22=0

We add all the numbers together, and all the variables

-7x+22=0

We move all terms containing x to the left, all other terms to the right

-7x=-22

x=-22/-7

x=3+1/7

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