(3x-1)(2+3x)=(3x-5)

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Solution for (3x-1)(2+3x)=(3x-5) equation: 



(3x-1)(2+3x)=(3x-5)

We move all terms to the left:

(3x-1)(2+3x)-((3x-5))=0

We add all the numbers together, and all the variables

(3x-1)(3x+2)-((3x-5))=0

We multiply parentheses ..

(+9x^2+6x-3x-2)-((3x-5))=0



We calculate terms in parentheses: -((3x-5)), so:

(3x-5)

We get rid of parentheses

3x-5

Back to the equation:

-(3x-5)



We get rid of parentheses

9x^2+6x-3x-3x-2+5=0

We add all the numbers together, and all the variables

9x^2+3=0

a = 9; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·9·3
Δ = -108
Delta is less than zero, so there is no solution for the equation

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