(3x-1)(2+3x)=(3x-5)(3x-5)

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Solution for (3x-1)(2+3x)=(3x-5)(3x-5) equation:



(3x-1)(2+3x)=(3x-5)(3x-5)
We move all terms to the left:
(3x-1)(2+3x)-((3x-5)(3x-5))=0
We add all the numbers together, and all the variables
(3x-1)(3x+2)-((3x-5)(3x-5))=0
We multiply parentheses ..
(+9x^2+6x-3x-2)-((3x-5)(3x-5))=0
We calculate terms in parentheses: -((3x-5)(3x-5)), so:
(3x-5)(3x-5)
We multiply parentheses ..
(+9x^2-15x-15x+25)
We get rid of parentheses
9x^2-15x-15x+25
We add all the numbers together, and all the variables
9x^2-30x+25
Back to the equation:
-(9x^2-30x+25)
We get rid of parentheses
9x^2-9x^2+6x-3x+30x-2-25=0
We add all the numbers together, and all the variables
33x-27=0
We move all terms containing x to the left, all other terms to the right
33x=27
x=27/33
x=9/11

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