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(3x-1)(2x+12)=180
We move all terms to the left:
(3x-1)(2x+12)-(180)=0
We multiply parentheses ..
(+6x^2+36x-2x-12)-180=0
We get rid of parentheses
6x^2+36x-2x-12-180=0
We add all the numbers together, and all the variables
6x^2+34x-192=0
a = 6; b = 34; c = -192;
Δ = b2-4ac
Δ = 342-4·6·(-192)
Δ = 5764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5764}=\sqrt{4*1441}=\sqrt{4}*\sqrt{1441}=2\sqrt{1441}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-2\sqrt{1441}}{2*6}=\frac{-34-2\sqrt{1441}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+2\sqrt{1441}}{2*6}=\frac{-34+2\sqrt{1441}}{12} $
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