(3x-1)(2x+2)=0

Solution for (3x-1)(2x+2)=0 equation:

(3x-1)(2x+2)=0

We multiply parentheses ..

(+6x^2+6x-2x-2)=0

We get rid of parentheses

6x^2+6x-2x-2=0

We add all the numbers together, and all the variables

6x^2+4x-2=0

a = 6; b = 4; c = -2;
Δ = b2-4ac
Δ = 42-4·6·(-2)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8}{2*6}=\frac{-12}{12}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8}{2*6}=\frac{4}{12}
=1/3
$