(3x-1)(2x+5)3(2x-1)(x+2)=24

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Solution for (3x-1)(2x+5)3(2x-1)(x+2)=24 equation: 



(3x-1)(2x+5)3(2x-1)(x+2)=24

We move all terms to the left:

(3x-1)(2x+5)3(2x-1)(x+2)-(24)=0

We multiply parentheses ..

(+6x^2+15x-2x-5)3(2x-1)(x+2)-24=0

We multiply parentheses ..

(+6x^2+15x-2x-5)3(+2x^2+4x-1x-2)-24=0

We move all terms containing x to the left, all other terms to the right

(+6x^2+15x-2x-5)3(+2x^2+4x-1x-2)=24

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