(3x-1)(2x+7)-(x+1)(6x-5)=16

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Solution for (3x-1)(2x+7)-(x+1)(6x-5)=16 equation:



(3x-1)(2x+7)-(x+1)(6x-5)=16
We move all terms to the left:
(3x-1)(2x+7)-(x+1)(6x-5)-(16)=0
We multiply parentheses ..
(+6x^2+21x-2x-7)-(x+1)(6x-5)-16=0
We get rid of parentheses
6x^2+21x-2x-(x+1)(6x-5)-7-16=0
We multiply parentheses ..
6x^2-(+6x^2-5x+6x-5)+21x-2x-7-16=0
We add all the numbers together, and all the variables
6x^2-(+6x^2-5x+6x-5)+19x-23=0
We get rid of parentheses
6x^2-6x^2+5x-6x+19x+5-23=0
We add all the numbers together, and all the variables
18x-18=0
We move all terms containing x to the left, all other terms to the right
18x=18
x=18/18
x=1

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