(3x-1)(2x-3)=-3x(4-2x)

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Solution for (3x-1)(2x-3)=-3x(4-2x) equation: 



(3x-1)(2x-3)=-3x(4-2x)

We move all terms to the left:

(3x-1)(2x-3)-(-3x(4-2x))=0

We add all the numbers together, and all the variables

(3x-1)(2x-3)-(-3x(-2x+4))=0

We multiply parentheses ..

(+6x^2-9x-2x+3)-(-3x(-2x+4))=0



We calculate terms in parentheses: -(-3x(-2x+4)), so:

-3x(-2x+4)

We multiply parentheses

6x^2-12x

Back to the equation:

-(6x^2-12x)



We get rid of parentheses

6x^2-6x^2-9x-2x+12x+3=0

We add all the numbers together, and all the variables

x+3=0

We move all terms containing x to the left, all other terms to the right

x=-3

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