(3x-1)(2x-6)=0

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Solution for (3x-1)(2x-6)=0 equation:



(3x-1)(2x-6)=0
We multiply parentheses ..
(+6x^2-18x-2x+6)=0
We get rid of parentheses
6x^2-18x-2x+6=0
We add all the numbers together, and all the variables
6x^2-20x+6=0
a = 6; b = -20; c = +6;
Δ = b2-4ac
Δ = -202-4·6·6
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-16}{2*6}=\frac{4}{12} =1/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+16}{2*6}=\frac{36}{12} =3 $

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