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(3x-1)(3)=4(x+5)
We move all terms to the left:
(3x-1)(3)-(4(x+5))=0
We multiply parentheses
9x-(4(x+5))-3=0
We calculate terms in parentheses: -(4(x+5)), so:We get rid of parentheses
4(x+5)
We multiply parentheses
4x+20
Back to the equation:
-(4x+20)
9x-4x-20-3=0
We add all the numbers together, and all the variables
5x-23=0
We move all terms containing x to the left, all other terms to the right
5x=23
x=23/5
x=4+3/5
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