(3x-1)(3-x)+4x*4x+19=0

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Solution for (3x-1)(3-x)+4x*4x+19=0 equation:



(3x-1)(3-x)+4x*4x+19=0
We add all the numbers together, and all the variables
(3x-1)(-1x+3)+4x*4x+19=0
Wy multiply elements
16x^2+(3x-1)(-1x+3)+19=0
We multiply parentheses ..
16x^2+(-3x^2+9x+x-3)+19=0
We get rid of parentheses
16x^2-3x^2+9x+x-3+19=0
We add all the numbers together, and all the variables
13x^2+10x+16=0
a = 13; b = 10; c = +16;
Δ = b2-4ac
Δ = 102-4·13·16
Δ = -732
Delta is less than zero, so there is no solution for the equation

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