(3x-1)(3x+1)=(3x-1)(3x+1)

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Solution for (3x-1)(3x+1)=(3x-1)(3x+1) equation: 



(3x-1)(3x+1)=(3x-1)(3x+1)

We move all terms to the left:

(3x-1)(3x+1)-((3x-1)(3x+1))=0

We use the square of the difference formula

9x^2+9x^2-1+1=0

We add all the numbers together, and all the variables

18x^2=0

a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{36}=0$

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