(3x-1)(3x+1)=15

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Solution for (3x-1)(3x+1)=15 equation:



(3x-1)(3x+1)=15
We move all terms to the left:
(3x-1)(3x+1)-(15)=0
We use the square of the difference formula
9x^2-1-15=0
We add all the numbers together, and all the variables
9x^2-16=0
a = 9; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·9·(-16)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*9}=\frac{-24}{18} =-1+1/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*9}=\frac{24}{18} =1+1/3 $

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