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(3x-1)(4x+2)=(2x+1)(6x-2)
We move all terms to the left:
(3x-1)(4x+2)-((2x+1)(6x-2))=0
We multiply parentheses ..
(+12x^2+6x-4x-2)-((2x+1)(6x-2))=0
We calculate terms in parentheses: -((2x+1)(6x-2)), so:We get rid of parentheses
(2x+1)(6x-2)
We multiply parentheses ..
(+12x^2-4x+6x-2)
We get rid of parentheses
12x^2-4x+6x-2
We add all the numbers together, and all the variables
12x^2+2x-2
Back to the equation:
-(12x^2+2x-2)
12x^2-12x^2+6x-4x-2x-2+2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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