(3x-1)(4x-1)=

Solution for (3x-1)(4x-1)= equation:

(3x-1)(4x-1)=

We move all terms to the left:

(3x-1)(4x-1)-()=0

We add all the numbers together, and all the variables

(3x-1)(4x-1)=0

We multiply parentheses ..

(+12x^2-3x-4x+1)=0

We get rid of parentheses

12x^2-3x-4x+1=0

We add all the numbers together, and all the variables

12x^2-7x+1=0

a = 12; b = -7; c = +1;
Δ = b2-4ac
Δ = -72-4·12·1
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-1}{2*12}=\frac{6}{24}
=1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+1}{2*12}=\frac{8}{24}
=1/3
$