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(3x-1)(x-3)-(4-5x)(3x-4)=6(x-7)-(3x+5)2
We move all terms to the left:
(3x-1)(x-3)-(4-5x)(3x-4)-(6(x-7)-(3x+5)2)=0
We add all the numbers together, and all the variables
(3x-1)(x-3)-(-5x+4)(3x-4)-(6(x-7)-(3x+5)2)=0
We multiply parentheses ..
(+3x^2-9x-1x+3)-(-5x+4)(3x-4)-(6(x-7)-(3x+5)2)=0
We calculate terms in parentheses: -(6(x-7)-(3x+5)2), so:We add all the numbers together, and all the variables
6(x-7)-(3x+5)2
We multiply parentheses
6x-6x-42-10
We add all the numbers together, and all the variables
-52
Back to the equation:
-(-52)
(+3x^2-9x-1x+3)-(-5x+4)(3x-4)+52=0
We get rid of parentheses
3x^2-9x-1x-(-5x+4)(3x-4)+3+52=0
We multiply parentheses ..
3x^2-(-15x^2+20x+12x-16)-9x-1x+3+52=0
We add all the numbers together, and all the variables
3x^2-(-15x^2+20x+12x-16)-10x+55=0
We get rid of parentheses
3x^2+15x^2-20x-12x-10x+16+55=0
We add all the numbers together, and all the variables
18x^2-42x+71=0
a = 18; b = -42; c = +71;
Δ = b2-4ac
Δ = -422-4·18·71
Δ = -3348
Delta is less than zero, so there is no solution for the equation
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